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4x^2-4x=20.08
We move all terms to the left:
4x^2-4x-(20.08)=0
We add all the numbers together, and all the variables
4x^2-4x-20.08=0
a = 4; b = -4; c = -20.08;
Δ = b2-4ac
Δ = -42-4·4·(-20.08)
Δ = 337.28
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-\sqrt{337.28}}{2*4}=\frac{4-\sqrt{337.28}}{8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+\sqrt{337.28}}{2*4}=\frac{4+\sqrt{337.28}}{8} $
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